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DAY function

Evaluates a date expression and returns a day of the month as an INTEGER value from 1 to 31, inclusive.

Syntax

DAY ( date ) 

DAY ( datetime-expression ) 

date
datetime-expression
Example

This procedure determines the date one year from a given date, allowing for leap years. You could simply determine a date 365 days later by adding 365 to the d1 variable, but that might not produce the correct result (for example, 1/1/92 + 365 days is 12/31/92).

r-day.p
DEFINE VARIABLE d1    AS DATE    NO-UNDO LABEL "Date". 
DEFINE VARIABLE d2    AS DATE    NO-UNDO LABEL "Same date next year". 
DEFINE VARIABLE d-day AS INTEGER NO-UNDO. 
DEFINE VARIABLE d-mon AS INTEGER NO-UNDO. 
REPEAT: 
  SET d1. 
  d-day = DAY(d1). 
  d-mon = MONTH(d1). 
  IF d-mon = 2 AND d-day = 29 THEN d-day = 28. 
  d2 = DATE(d-mon,d-day,YEAR(d1) + 1). 
  DISPLAY d2. 
END. 

See also

ADD-INTERVAL function, DATE function, DATE-FORMAT attribute, DATETIME function, DATETIME-TZ function, ETIME function, INTERVAL function, ISO-DATE function, MONTH function, MTIME function, NOW function, TIME function, TIMEZONE function, TODAY function, WEEKDAY function, YEAR function, YEAR-OFFSET attribute


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